Let's say I have a table like this: #+NAME: numbers | one | | two | | three | I want to run through those numbers in a shell code block, but it I pass in table as a variable, it only sees the first number. #+begin_src shell :results output :var n=numbers echo $n #+end_src #+RESULTS: : one In Ruby it sees the numbers as an array: #+begin_src ruby :results output :var n=numbers puts n puts n.class #+end_src #+RESULTS: : one : two : three : Array And in R sees them as a data.table with one column. Both are very easy to iterate over, of course. I looked at the docs, but didn't see this covered, then I looked at ob-shell.el and saw the "org-babel--variable-assignments:bash_array" function, which might or might not be relevant, but it's all beyond my comprehension. Is there a way to get my shell code seeing all of the elements in the column? Thanks, Bill -- William Denton :: Toronto, Canada --- Listening to Art: https://listeningtoart.org/ https://www.miskatonic.org/ --- GHG.EARTH: https://ghg.earth/ Caveat lector. --- STAPLR: https://staplr.org/
William, try #+begin_src shell :results output :var n=numbers echo ${n[1]} #+end_src cheers, Greg
On 3 April 2021, Greg Minshall wrote: > #+begin_src shell :results output :var n=numbers > echo ${n[1]} > #+end_src Aha, it's in an array but I didn't see it! Thanks. Org was doing it magic but I got confused by bash. #+NAME: numbers | one | | two | | three | #+begin_src shell :results output :var n=numbers for i in "${n[@]}"; do echo $i done #+end_src #+RESULTS: : one : two : three Bill -- William Denton :: Toronto, Canada --- Listening to Art: https://listeningtoart.org/ https://www.miskatonic.org/ --- GHG.EARTH: https://ghg.earth/ Caveat lector. --- STAPLR: https://staplr.org/
Hi Greg and William,
Greg Minshall writes:
> William,
>
> try
>
> #+begin_src shell :results output :var n=numbers
> echo ${n[1]}
> #+end_src
>
> cheers, Greg
I don't know if I'm saying something wrong, but wouldn't it be better
this way?:
#+begin_src shell :results output :var n=numbers
echo ${n[@]}
#+end_src
echo ${n[1]} returns the second element (two) of the list (0, returns
one and 2 returns three)
Best regards,
Juan Manuel
Hello,
William Denton <wtd@pobox.com> writes:
> On 3 April 2021, Greg Minshall wrote:
>
>> #+begin_src shell :results output :var n=numbers
>> echo ${n[1]}
>> #+end_src
>
> Aha, it's in an array but I didn't see it! Thanks. Org was doing it magic but
> I got confused by bash.
interestingly I asked a similar question in #org-mode yesterday. I came
up with this approach:
* table test
** user data
#+name: userdata
| uid | name | foo | bar |
| a2s | a2 | afoo | abar |
| b2s | b2 | bfoo | bbar |
| c2s | c2 | c foo | cbar |
** code
#+begin_src sh :var userdata=userdata :separator , :results raw
echo "$userdata" | while read line ; do
IFS=','
echo "$line" | while read u n f b ; do
echo "u: $u n: $n f: $f b: $b"
done
done
#+end_src
This looks a bit clumsy, but should also work with shell that doesn't
support (2D) array type variables.
Regards
hmw